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Integrated rate equation for association
- Drug discovery
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3 months 1 week ago #1
by Drug discovery
Integrated rate equation for association was created by Drug discovery
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- Arnoud
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3 months 1 week ago #2
by Arnoud
Replied by Arnoud on topic Integrated rate equation for association
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3 months 1 week ago #3
by Drug discovery
Replied by Drug discovery on topic Integrated rate equation for association
Thank you Arnoud. I got the steps before and after integration but not the actual integration step.
I was keen to how the variables were separated from the previous step and the subsuequent integration to end up with Ka.C.Rmax / (kaC+Kd)x(1-e*(kaC+Kd)t Just couldn't figure.. yet
Thank you as always for the quick repsonse and amazing contirbution!!
cheers
I was keen to how the variables were separated from the previous step and the subsuequent integration to end up with Ka.C.Rmax / (kaC+Kd)x(1-e*(kaC+Kd)t Just couldn't figure.. yet
Thank you as always for the quick repsonse and amazing contirbution!!
cheers
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- thomeseliana
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2 months 1 hour ago #4
by thomeseliana
Replied by thomeseliana on topic Integrated rate equation for association
When discussing the integrated rate equation for association, it’s essential to understand that it describes the time-dependent formation of a complex between two molecules (like a ligand and a receptor). The equation relates the concentration of the complex to the rate constants for association and dissociation. [Deleted]
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- NMCCANN2
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1 month 2 weeks ago #5
by NMCCANN2
Replied by NMCCANN2 on topic Integrated rate equation for association
I've tried to go through this derivation myself and it is not straight forward. There is a lot of strange algebraic manipulation to get there. I was only able to solve it by starting with the integrated rate equation and working backwards toward the differential equation.
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1 month 2 weeks ago #6
by NMCCANN2
Replied by NMCCANN2 on topic Integrated rate equation for association
Here, I drew out the differentiation from the integrated form to the differential form.
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